Math, asked by bikasdutta2013, 1 month ago

Evaluate:
lim [2sin(x-1)/(x-1)]
x->1​

Answers

Answered by jitendra12iitg
0

Answer:

The answer is 2

Step-by-step explanation:

                  Formula to be used:

                      \boxed{\displaystyle \lim_{x\to 0}\dfrac{\sin x}{x}=1}

Given limit

                  =\displaystyle \lim_{x\to 1}\dfrac{2\sin(x-1)}{x-1}

Substitute x-1=y\Rightarrow x=y+1

So if x\to 1 then y\to 0  

                  =\displaystyle \lim_{y\to 0}\dfrac{\sin y}{y}=2\times \lim_{y\to 0}\dfrac{\sin y}{y}=2(1)=2

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