evaluate lim(cos x )^cot^2x
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EXPLANATION.
As we know that,
First we put the value of x = 0 in equation and check their form, we get.
We can see that it is a form of 1^∞,
So, we can take log on both sides, we get.
Again, put the value of x = 0 in equation and check their form, we get.
As we can see that it is the form of 0/0 form,
Now we can apply L-Hopital rule, we get.
Differentiate (tan x)².
⇒ d(tan x)²/dx = 2.tan x. sec²x.
Put the value of x = 0 in equation, we get.
MORE INFORMATION.
Some limits which do not exists.
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