Question

Evaluate: lim x=1 2x^2-3x+1/x^2-1 .​

Answer 1

Answer:

$\frac{2x^2-3x+1}{x^2-1} \\= \frac{\left(2x-1\right)\left(x-1\right)}{x^2-1}$

$\frac{\left(2x-1\right)\left(x-1\right)}{\left(x+1\right)\left(x-1\right)}\\= \frac{2x-1}{x+1}$

By Substituting :

2 ( 1 ) - 1 / 1 + 1

= 1 / 2

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