Question

evaluate: lim x→π/4 sin2x
answer correct​

Answer 1

Answer:

1

Step-by-step explanation:

$\sin(2x) \\ = 2 \sin(x) \cos(x) \\ putting \: x = \frac{\pi}{4} \\ = 2 \sin( \frac{\pi}{4} ) \cos( \frac{\pi}{4} ) \\ = 2 \times \frac{1}{ \sqrt{2} } \times \frac{1}{ \sqrt{2} } \\ = \frac{2}{2} \\ = 1$

HOPE IT HELPS :D

Answer 2

$\displaystyle \sf{ } \: \lim_{x \to \frac{\pi}{4} } \: \sin 2x = 1$

Given :

$\displaystyle \sf{ } \: \lim_{x \to \frac{\pi}{4} } \: \sin 2x$

To find :

The value of limit

Solution :

Step 1 of 2 :

Write down the given limit

Here the given limit is

$\displaystyle \sf{ } \: \lim_{x \to \frac{\pi}{4} } \: \sin 2x$

Step 2 of 2 :

Find the value

$\displaystyle \sf{ } \: \lim_{x \to \frac{\pi}{4} } \: \sin 2x$

$\displaystyle \sf{ } \: = \sin \frac{2\pi}{4}$

$\displaystyle \sf{ } \: = \sin \frac{\pi}{2}$

$\displaystyle \sf{ } \: = 1$

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