Question

evaluate
lim(x->0) [sinx/x]^[sinx/x-sinx]

Answer 1

Answer:

0.095

Step-by-step explanation:

$\lim_{x \to \ 0}sin 1^s^i^n^ 1^-^s^i^n^ 0$

$= 0.01^0^.^0^1^-^0=0.01^{0.01}=0.095$