Question

Evaluate :- Lim(x-> 3 ) ( x²-8x+15/x-5)

Answer 1

$\lim_{x \to 3} \frac { x^2 - 8x + 15} {x-5}$

= $\lim_{x \to 3} \frac { (x - 3 )(x-5)} {x-5}$

= $\lim_{x \to 3} (x-3)$

= 3 - 3

= 0

Answer 2

Hi,

Please see the attached file!

Thanks