Math, asked by rawshan8, 10 months ago

evaluate...Lim( x tends to 0)[ tan2x-sin2x]/x^3​

Answers

Answered by uttamkumarchoudhary
1

2xtan(2x)

×2−(x...0lim )

2x

sin(2x)

×2

=(1×2)−(1×2)

=0

0

hence zero is the answer

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