evaluate lim x tends to zero (tan x)^(sin2x)
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Step-by-step explanation:
100 hundreds = thousand
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Answer:
lim x->0 (tanx)^sin2x
Let, y = (tanx)^sin2x
lim x->0 y = (tanx)^sin2x
lim x->0 logy = sin2x . log(tanx)
Solving R.H.S-
log(tanx) / (1/sin2x)
Applying L hospital rule-
Sin2x/cos2x
= tan2x
Now,
Lim x->0 log y = tan2x
y = e^0
y = 1
so, lim x->0 (tanx)^sin2x the Answer is 1
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