Math, asked by amairacruz, 9 months ago

evaluate limit ((1-x)^n-1)/x where x➡️0​

Answers

Answered by shobhabeeragmailcom
0

Answer:

274893. bnm,kncksksndmxm m mkdksnd dmxxxxxknxnxjdkskskdkdkmfmfmdmdmdmdkcif

Answered by hrn21agmailcom
1

Answer:

n

Step-by-step explanation:

(1-x)^n = 1 + nC1 (x) + nC2(x)^2 +.....(x)^n

(1-x)^n - 1 = nC1 (x) + nC2(x)^2 +.....(x)^n

[ (1-x)^n - 1 ] /x = nC1 + nC2 x + ....nC1x^(n-1)

[ (1-x)^n - 1 ] /x as x → 0.......

nC1 + 0 +0 .....0 = nC1 = n

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