Evaluate limit n tends to -1 (1+x+x2±...+x10)
That is x square and x raised to 10
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A short proof:
(1+
x
n
)n=enlog(1+
x
n
)
Since log(1+x)=x+O(x2) when x→0, we have nlog(1+
x
n
)=x+O(
x2
n
) when n→+∞
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