evaluate limit x->0+ x^x ??
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LHL will be 1/x
RHL will be x
Hence the Limit doesn't exist here
RHL will be x
Hence the Limit doesn't exist here
Ronny13:
correct ... but limit is given from 0+ .... so limit exists =1
0- is not in dom ... so will not check that ... from 0+ limit is e^0+
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