Question

Evaluate limit x tends to zero ((cos4x-1)^1/2)/x^2

Answer 1

Answer:

∞

Step-by-step explanation:

By L'Hopital's Rule, the limit is equal to the limit of

-4 × ( (sin 4x) / 4x ) × ( 1 / ( cos 4x - 1 )^(1/2) )

As -4 is constant and the second factor tends to 1, while the last factor tends to ∞, the limit is ∞ for this function, and so also for the original function.