Question

evaluate log 6 + 2log5+log 4 -log 3 -log 2

Answer 1

Answer:

2

Step-by-step explanation:

using formula

log m*n=logm+logn

=>log6+2log5+log4-log3-log2

=log2*3+2log5+log2*2-log3-log2

=log2+log3+2log5+log2+log2-log3-log2

=2log2+2log5=2(log2+log5)

=2(log2*5)=2log10=2*1=2