evaluate log 6 + 2log5+log 4 -log 3 -log 2
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Answered by
1
Answer:
2
Step-by-step explanation:
using formula
log m*n=logm+logn
=>log6+2log5+log4-log3-log2
=log2*3+2log5+log2*2-log3-log2
=log2+log3+2log5+log2+log2-log3-log2
=2log2+2log5=2(log2+log5)
=2(log2*5)=2log10=2*1=2
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