Math, asked by shakoorhamna60, 17 days ago

Evaluate log 81 to base 3√3​

Answers

Answered by bson
7

log A base b = log a/log b numerator and denominator are to the same base

log 81 = log 3⁴ = 4log 3

log 3root3 = log 3^(3/2) = 3/2 ×log3

4log3 ÷ 3/2 log3

4×2/3 = 8/3

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