Math, asked by chineny96, 7 months ago

Evaluate: log 9 base 81

Answers

Answered by anushkasharma8840
6

Step-by-step explanation:

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Answered by Divyansh50800850
10

\star\bold\red{Solution:-}

\implieslog 9 81 \implies log9 9²

Now , we know,

From logarithm properties that

\implieslog a^b = b* log a

\implieslog9 9² = 2*log9 9

\implieslog9 81 = 2*log9 9

Now we know that loga a = 1

\implieslog9 81 = 2*log9 9 = 2*1 = 2

Hence, the exact value of log9 81 = 2

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