evaluate Log base 2 * 1/128
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Answered by
2
Answer:
Rewrite
log
2
(
1
128
)
as
log
2
(
1
)
−
log
2
(
128
)
.
log
2
(
1
)
−
log
2
(
128
)
Logarithm base
2
of
1
is
0
.
0
−
log
2
(
128
)
Logarithm base
2
of
128
is
7
.
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