Math, asked by smd556902, 5 days ago

evaluate log2 45 as product of X and Y if X=log2 3 and Y=log2=5​

Answers

Answered by llchummill
0

Answer:

Logarithm Calculator log(x)

with b being the base, x being a real number, and y being an exponent. For example, 23 = 8 ... log2(8) = 3 (log base 2 of 8) The exponential is 23 =

Answered by pulakmath007
1

SOLUTION

GIVEN

\displaystyle \sf{ X =  log_{2}(3) \:  \: and \:  \:  Y =  log_{2}(5)  }

TO DETERMINE

\displaystyle \sf{  log_{2}(45)  \:  \: in \: terms \: of \: X  \: and \:  Y  }

FORMULA TO BE IMPLEMENTED

We are aware of the formula on logarithm that

 \sf{1.  \:  \: \:  log( {a}^{n} ) = n log(a)  }

 \sf{2. \:  \:  log(ab) =  log(a)   +  log(b) }

 \displaystyle \sf{3. \:  \:  log \bigg( \frac{a}{b}  \bigg)  =  log(a) -  log(b)  }

 \sf{4. \:  \:   log_{a}(a)   = 1}

EVALUATION

Here it is given that

\displaystyle \sf{ X =  log_{2}(3) \:  \: and \:  \:  Y =  log_{2}(5)  }

Now

\displaystyle \sf{  log_{2}(45) }

\displaystyle \sf{ =   log_{2}( {3}^{2}  \times 5) }

\displaystyle \sf{ =   log_{2}( {3}^{2} )   +  log_{2}(5)  }

\displaystyle \sf{ = 2  log_{2}( {3}^{} )   +  log_{2}(5)  }

\displaystyle \sf{ = 2  X + Y  }

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