Evaluate log3 5 + log3 7 + log3 9 = log3 x
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Answer:
log3 5 + log3 7 + log 3 9 = log3 x
so by using the property log a + log b = log ab
there for
log3 ( 5×7×9) = log3 x
log3 (315) = log3 x
so
x = 315
nb: this problem is solved in an aspect of log to the base 3 not as log cube or log multiplied by 3
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