evaluate :- log³ x+6=2
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Step-by-step explanation:
First, we should know the value of log^3. The value of log^3 is 0.4771.
Lets take log^3 value is 0.47. On subsuiting we get:
0.47×+6=2.
2-6=0.47×.
-4=0.47×.
× value is -4/0.47.
×=-8.41.
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