evaluate
Log5 √5 + log3√27?
Rahuldeep:
Option are 1/3,2,3/7,6
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=log(5) √5 + log(3) √27
=log(5) 5^1/2 + log(3) 27^1/2
=1/2{log(5) 5} + 1/2{log(3) 3³}
=1/2 + 1/2×3{log(3) 3}
=1/2+3/2
=4/2
=2.
=log(5) 5^1/2 + log(3) 27^1/2
=1/2{log(5) 5} + 1/2{log(3) 3³}
=1/2 + 1/2×3{log(3) 3}
=1/2+3/2
=4/2
=2.
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