evaluate log6base^72-log6^2
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3
Answer:
Formula:
logb(x) = y, if by = x
Input:
x = 72
b = 6
Solution:
y = log6 72
= log(6 x 6 x 2)
= log6(6) + log6(6) + log6(2)
= 1 + 1 + 0.3869
= 2.3869
log6(72) = 2.3869
Step-by-step explanation:
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