Question

Evaluate Lt Ix-51 at x = 1​

Answer 1

Answer:

x→0

lim

x

(x+1)

5

−1

Put x+1=y

So, y→1 as x→0

=

y→1

lim

y−1

y

5

−1

5

=5⋅1

5−1

[

x→a

lim

x−a

x

n

−a

n

=na

n−1

]

=5

∴

x→0

lim

x

(x+5)

5

−1

=5

Step-by-step explanation:

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