Question

evaluate lt n-> 1+2+3........+n/n2

Answer 1

I hope u understand....

Answer 2

Answer:

Step-by-step explanation:

1 + 2 + 3 + ...... + n = n(n + 1)/2

(1 + 2 + 3 + ...... + n) / n^2=

= n(n + 1)/(2n^2)

= (n + 1) / (2n)