Question

Evaluate :
n!/r!(n-r)!for
n=8 and r= 6​

Answer 1

Answer:

The solution for $\dfrac{n!}{r!(n-1)!}$ is $\dfrac{1}{90}$

Step-by-step explanation:

Given,

• n = 8
• r = 6

We have to evaluate,

$\dfrac{n!}{r!(n-1)!}$ -------------------(i)

put n = 8 and r = 6 in above equation (i)

$\dfrac{8!}{6!(8-1)!}$

$\dfrac{8!}{6!7!}$ -------------------(ii)

where,

• 8! = $8\times7\times6\times5\times4\times3\times2\times1$
• 7! = $7\times6\times5\times4\times3\times2\times1$
• 6! = $6\times5\times4\times3\times2\times1$

put above values in equation (ii)

$\dfrac{8\times7\times6\times5\times4\times3\times2\times1}{7\times6\times5\times4\times3\times2\times1\times6\times5\times4\times3\times2\times1}$

= $\dfrac{1}{6\times5\times3\times1}$

= $\dfrac{1}{90}$

Answer 2

Step-by-step explanation:

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