Question

Evaluate
of 2tan²-45°+cot²45°-sin60°​

Answer 1

$2 {tan}^{2} 45 + {cot}^{2} 45 - sin60 \\ = 2 + 1 - \frac{ \sqrt{3} }{2} \\ = \frac{4 + 2 - \sqrt{3} }{2} \\ = \frac{6 - \sqrt{3} }{2}$

Answer 2

$\frac{6 - \sqrt{3} }{2 }$

is the answer..

Additional information :

$tan \: 45 \degree = 1 \\ cot \: 45 \degree = 1 \\ sin \: 60 \degree = \frac{ \sqrt{3} }{2}$

Refer the attachment for complete answer ✔️