Math, asked by varshinisivakumar0, 2 months ago


Evaluate :
pi/2 integrate -pi/2 x cos x dx​

Answers

Answered by HarshitKumar07
1

Answer: consider, I=∫  

0

π/2

​  

sinxcosx dx  

Let t=sinx⟹dt=cosxdx

x→0→π/2  

t→0→1  

⇒I=∫  

0

1

​  

t dt  

⇒ [  

2

t  

2

 

​  

]  

0

1

​  

=  

2

1

Step-by-step explanation:

Answered by ppritikumari489
0

Step-by-step explanation:

I don't know answer please tell

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