Evaluate :
pi/2 integrate -pi/2 x cos x dx
Answers
Answered by
1
Answer: consider, I=∫
0
π/2
sinxcosx dx
Let t=sinx⟹dt=cosxdx
x→0→π/2
t→0→1
⇒I=∫
0
1
t dt
⇒ [
2
t
2
]
0
1
=
2
1
Step-by-step explanation:
Answered by
0
Step-by-step explanation:
I don't know answer please tell
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