Question

evaluate please help I need your help

Answer 1

$Given, 2 * 9^{ \frac{3}{2} } * 9^{ \frac{-1}{2} }$

Note: When multiplying the two powers that have the same base, you can add the exponents.

$2 * 9^{ (\frac{3}{2} - \frac{1}{2} ) }$

$2 * 9^{ \frac{2}{2} }$

$2 * 9^{1}$

2 * 9

18.


Hope this helps!

Answer 2

Hey mate..
=========

Given,

$2 \times 9 {}^{ \frac{3}{2} } \times 9 {}^{ \frac{ - 1}{2} }$

We know,

$a {}^{m} \times a {}^{n} = a {}^{(m + n)}$

So,

$2 \times 9 {}^{ (\frac{3}{2} - \frac{1}{2} )} \\ \\ = 2 \times 9 {}^{ (\frac{2}{2})} \\ \\ = 2 \times 9 \\ \\ = 18$
Hope it helps...☺