Question

evaluate ..... please its urgent​

Answer 1

Step-by-step explanation:

this is your answer

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Answer 2

8.0244

Step-by-step explanation:

$\frac{3 \sin 3B + 2 \times \cos(2B + 5)}{2\cos 3B - \sin (2B - 10)}$...........(i)

Given that, $B = 20$ on putting the value in above equation (i) we get

$\frac{3 \sin 60 + 2 \cos(45)}{2 \cos 60 - \sin (30)}$

⇒ $\frac{3 \times\frac{\sqrt3}{2} + 2 \times\frac{1}{\sqrt2}}{2 \times\frac{1}{2} - \frac{1}{2}}$

⇒ $\frac{\frac{3 \times\sqrt{3} + 2 \times\sqrt2}{2}}{\frac{1}{2}}$

⇒ ${3 \times \sqrt{3} + 2 \times \sqrt2}$

⇒ ${3 \times\ 1.732 + 2 \times 1.414}$

⇒ ${5.196 + 2.828}$

⇒ ${8.0244}$