evaluate quaadritic equation x^2+5x+6=0
Answers
Answered by
7
Hello ☺️❤️
_______________________
x² + 5x + 6 = 0
⇒ x² + 2x + 3x + 6 = 0
⇒ x ( x + 2 ) + 3 ( x + 2 ) = 0
⇒ ( x + 2 ) ( x + 3 ) = 0
Here,
x + 2 = 0
⇒ x = - 2
And,
x + 3 = 0
⇒ x = - 3
_______________________
x² + 5x + 6 = 0
⇒ x² + 2x + 3x + 6 = 0
⇒ x ( x + 2 ) + 3 ( x + 2 ) = 0
⇒ ( x + 2 ) ( x + 3 ) = 0
Here,
x + 2 = 0
⇒ x = - 2
And,
x + 3 = 0
⇒ x = - 3
Answered by
4
Hello friends!!
Here is your answer :
=> x² + 5x + 6 = 0
Method 1 : BY FACTORISATION
x² + 5x + 6 = 0
x² + 3x + 2x + 6 = 0
x ( x + 3 ) + 2 ( x + 3 ) = 0
( x + 3 ) + ( x + 2 ) = 0
x = - 3 or - 2
___________________________________
Hope it helps ☺️ ☺️ ☺️
Here is your answer :
=> x² + 5x + 6 = 0
Method 1 : BY FACTORISATION
x² + 5x + 6 = 0
x² + 3x + 2x + 6 = 0
x ( x + 3 ) + 2 ( x + 3 ) = 0
( x + 3 ) + ( x + 2 ) = 0
x = - 3 or - 2
___________________________________
Hope it helps ☺️ ☺️ ☺️
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