evaluate ques 5 pl solve it
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Hi , there !!!
here is your answer !!!
( sin47° / cos43° )² + ( cos43° / sin47° ) ² - 4cos²45°
sin (90-47 ) = cos43°
and
Cos ( 90- 43) = sin 47
from this property on putting in given equation we get
( Cos43 °/ Cos43 °) ² + ( sin47° / sin47 ° )² - 4
Cos²45
=> 1² + 1² - 4 ( 1 / 2 )
2 - 2
= 0
hope it helps you !!!
thanks !!!
Ranjan kumar
here is your answer !!!
( sin47° / cos43° )² + ( cos43° / sin47° ) ² - 4cos²45°
sin (90-47 ) = cos43°
and
Cos ( 90- 43) = sin 47
from this property on putting in given equation we get
( Cos43 °/ Cos43 °) ² + ( sin47° / sin47 ° )² - 4
Cos²45
=> 1² + 1² - 4 ( 1 / 2 )
2 - 2
= 0
hope it helps you !!!
thanks !!!
Ranjan kumar
deepalijain25:
thanks
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