Evaluate : root x ^a-b * root x^b-c * root x^c-a
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Answer:
root x^a-b*root x ^ b-c* root x^c-a
=x^(a-b)/2*x^(b-c)/2*x^(c-a)/2
=x^(a/2-b/2+b/2-c/2+c/2-a/2)
=x^0
=1
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