Math, asked by mandeepkaur889, 1 day ago

Evaluate : root x ^a-b * root x^b-c * root x^c-a

Answers

Answered by bagkakali
0

Answer:

root x^a-b*root x ^ b-c* root x^c-a

=x^(a-b)/2*x^(b-c)/2*x^(c-a)/2

=x^(a/2-b/2+b/2-c/2+c/2-a/2)

=x^0

=1

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