Question

Evaluate
(root32-root5)¹÷³×(root32+root5)¹÷³​

Answer 1

I don't no

hope it will not be help you

so mark as brainlist

Answer 2

We have to evaluate   $(\sqrt32-\sqrt5)^\frac{1}{3} \times (\sqrt32+\sqrt5)^\frac{1}{3}$

A number raised to  $\frac{1}{3}$  means its cube root.

So,

$(^3\sqrt{\sqrt32-\sqrt5}) {\times} (^3\sqrt{\sqrt32+\sqrt5})$

$=(\sqrt32-\sqrt5)\times(\sqrt32+\sqrt5)$

This is in the form (a-b) × (a+b)

(a-b) × (a+b) = (a)² - (b)²

Here,

• $a=\sqrt32$

• $b=\sqrt5$

$\bold{(\sqrt32-\sqrt5)\times(\sqrt32+\sqrt5) = (\sqrt32)^2-(\sqrt5)^2}$

$\bold{= 32 - 5}$

$\boxed{\bold{\therefore(\sqrt32-\sqrt5)^\frac{1}{3} \times (\sqrt32+\sqrt5)^\frac{1}{3} = 27}}$