Math, asked by navin5451, 1 month ago

evaluate root5 +root2 +(root 8+ root 5 )^2​

Answers

Answered by rohangupta0424
1

Answer:

\sqrt{5}+\sqrt{2}+\left(\sqrt{8}+\sqrt{5}\right)^2

\sqrt{5}+\sqrt{2}+\left[(\sqrt{8})^2+2(\sqrt{8})(\sqrt{5})} +(\sqrt{5}\right)^2]

\sqrt{5}+\sqrt{2}+\left[8+2*2(\sqrt{2}\sqrt{5}) +5]

\sqrt{5}+\sqrt{2}+\left[8+4\sqrt{2}\sqrt{5} +5]

\sqrt{5}+\sqrt{2}+\left[8+4\sqrt{10} +5]

\sqrt{5}+\sqrt{2}+\left(13+4\sqrt{10})

\sqrt{5}+\sqrt{2}+13+4\sqrt{10}

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