Math, asked by simrankerketta007, 3 days ago

evaluate sec 17°/cosec 73°+ tan 78°/cot 12°+cos²60°+ tan²45°


ASAP ​

Answers

Answered by rishabhshah2609
1

Answer:

11/4

Step-by-step explanation:

sec17/cosec73+tan78/cot12+cos²60+tan²45

We know sec(90-Φ)=cosecΦ

so sec17=sec(90-73)=cosec73

So,

cosec73/cosec73+tan78/cot12+cos²60+tan²45

1+tan78/cot12+(1/2)²+(1/√2)²  (cos60=1/2 and tan45=1/√2)

So,1+tan78/cot12+1/4+1/2

(4+1+2)/4 +tan78/cot12

7/4+tan78/cot12

Now tan(90-Φ)=cotΦ

So tan78=tan(90-12)

=cot12

So,

7/4+cot12/cot12

7/4+1

11/4

Answered by Anonymous
4

Answer:

The answer is 1 + 1 + 1/4 + 1*1

Now just solve it..

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