evaluate sec 17°/cosec 73°+ tan 78°/cot 12°+cos²60°+ tan²45°
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Answers
Answered by
1
Answer:
11/4
Step-by-step explanation:
sec17/cosec73+tan78/cot12+cos²60+tan²45
We know sec(90-Φ)=cosecΦ
so sec17=sec(90-73)=cosec73
So,
cosec73/cosec73+tan78/cot12+cos²60+tan²45
1+tan78/cot12+(1/2)²+(1/√2)² (cos60=1/2 and tan45=1/√2)
So,1+tan78/cot12+1/4+1/2
(4+1+2)/4 +tan78/cot12
7/4+tan78/cot12
Now tan(90-Φ)=cotΦ
So tan78=tan(90-12)
=cot12
So,
7/4+cot12/cot12
7/4+1
11/4
Answered by
4
Answer:
The answer is 1 + 1 + 1/4 + 1*1
Now just solve it..
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