Math, asked by nagmanaz, 1 year ago

Evaluate sec^2(90-theta) - cot ^2 theta / 2(sin^2 25°+sin ^2 65°

Answers

Answered by 1987shyamsundargoswa
0

Step-by-step explanation:

 {yy)yy {41)}^{?}  \times \frac{?}{?} }^{2}

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