evaluate sec 35/csc55+tan 32/cot 58
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Heya,
Given => sec35°/cosec55° + tan32°/cot58°
= sec(90° - 55°)/cosec55° + tan(90° - 58°)
/cot58°
= cosec55°/cosec55° + cot58°/cot58°
= 1 + 1
= 2. ....... Answer
Hope this helps....:)
Given => sec35°/cosec55° + tan32°/cot58°
= sec(90° - 55°)/cosec55° + tan(90° - 58°)
/cot58°
= cosec55°/cosec55° + cot58°/cot58°
= 1 + 1
= 2. ....... Answer
Hope this helps....:)
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0
Hope this help you...
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