Question

Evaluate sec 41 sin 49 + cos 49 cosec 41-2/root3*tan20*tan60*tan70 by 2( sin square 31° + sin square 59°)​

Answer 1

Answer:

$\frac{ \sec(41) \sin(49) + \cos(41) \cosec(41) - \frac{2}{ \sqrt{3} \tan(20) \tan(60) \tan(70) } }{2( \sin^{2}(31) + \sin^{2} (59) ) } \\ =$