Question

evaluate: sec 50 degree*sin 40 degree + cos 40 degree*cosec 40 degree

Answer 1

$\sec(50) \times \sin(40) + \cos(40) \times \cosec(40) \\ \\ \sec(90 - 40) \sin(40) + \cos(40) \cosec(40) \\ cosec(40) \sin(40) + \cos(40) \frac{1}{ \sin(40) } \\ = 1 + \cot(40) \\ this \: is \: your \: answer$