Question

evaluate: sec 50 degree*sin 40 degree + cos 40 degree*cosec 50 degree

Answer 1

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Answer 2

Answer:

Value of Sec50°sin40°+cos40°cosec50° = 2

Step-by-step explanation:

Value of sec50°sin40°+cos40°cosec50°

= sec(90°-40°)sin40°+cos40°cosec(90°-50°)

= cosec40°sin40°+cos40°sec40°

/* Since ,

i)sec(90°-A) = cosecA

ii) cosec(90°-A)=secA

*/

= $\frac{1}{sin40}\times sin40 + cos40 \times \frac{1}{cos40}$

After cancellation, we get

= $1+1$

= $2$

Therefore,

Value of Sec50°sin40°+cos40°cosec50° = 2

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