Math, asked by shiekhbilkees010, 8 months ago

evaluate sec square 60degree +sec0 degree

Answers

Answered by ksonakshi70
4

Answer:

 \sec {}^{2} (60)  +  \sec(0)  \\  = 2 {}^{2}  + 1 \\ =  4 + 1 \\  = 5

Answered by surendrasahoo
7

Answer:-

 {sec}^{2} (60 )+  \sec(0)  \\  =  {2}^{2}   + {1}^{2}  \\  = 4 + 1 \\  = 5

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