Math, asked by naazpreet13, 1 month ago

Evaluate: sec17°/cosec73° + tan68°/cot22°​

Answers

Answered by FloralSparks
3

 \\⠀⠀\bigstar \:⠀⠀⠀\underbrace\bold{\large\underline{Ꮧռʂաɛʀ᭄࿐: - }} \\

\huge\frac{sec 17°}{cosec 73° } + \huge\frac{tan68°}{cot22°}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\huge\frac{sec 17°}{cosec (90-17)° } + \huge\frac{tan68°}{cot(0-22)°}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\huge\frac{sec 17°}{ sec 17°} + \huge\frac{tan68°}{ tan68°}

⟹ 1

Answered by ItzJanvi10
5

Answer:

[tex]\begin{gathered} \\⠀⠀\bigstar \:⠀⠀⠀\underbrace\bold{\large\underline{Ꮧռʂաɛʀ᭄࿐: - }} \\ \end{gathered}[) tex]

⇝\huge\frac{sec 17°}{cosec 73° }

cosec73°

sec17°

+ \huge\frac{tan68°}{cot22°}

cot22°

tan68°

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

⟹\huge\frac{sec 17°}{cosec (90-17)° }

cosec(90−17)°

sec17°

+ \huge\frac{tan68°}{cot(0-22)°}

cot(0−22)°

tan68°

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

⟹\huge\frac{sec 17°}{ sec 17°}

sec17°

sec17°

+ \huge\frac{tan68°}{ tan68°}

tan68°

tan68°

⟹ 1

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