Evaluate: sec17°/cosec73° + tan68°/cot22°
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Answered by
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Answer:
[tex]\begin{gathered} \\⠀⠀\bigstar \:⠀⠀⠀\underbrace\bold{\large\underline{Ꮧռʂաɛʀ᭄࿐: - }} \\ \end{gathered}[) tex]
⇝\huge\frac{sec 17°}{cosec 73° }
cosec73°
sec17°
+ \huge\frac{tan68°}{cot22°}
cot22°
tan68°
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⟹\huge\frac{sec 17°}{cosec (90-17)° }
cosec(90−17)°
sec17°
+ \huge\frac{tan68°}{cot(0-22)°}
cot(0−22)°
tan68°
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⟹\huge\frac{sec 17°}{ sec 17°}
sec17°
sec17°
+ \huge\frac{tan68°}{ tan68°}
tan68°
tan68°
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