Question

Evaluate :
Sec243 – cot247' +
2(Sin235 + Sin255)
2 cos260.cot 22: cot268'
3(cos 44 + cos² 46)​

Answer 1

Answer:

sec²43-cot²47+2(sin²35+sin²55)2cos²60.cot22.cot68x3(cos²44+cos²46)

sec²43-tan²43 +2(sin²35+ cos²35).2cos²60.cot22.tan22x3(cos²44+sin²44)

1+2(1) x 2 x 1/4 x 3(1)

1+(1x3)

4

hope this will help you