Question

Evaluate: (sec29°/ cosec 61°) + 2 cot 8° cot 17° cot 45° cot 73° cot 82° - 3 (sin2 38° + sin2 52°)

Answer 1

zero will be the answer

Answer 2

Answer:

Step-by-step explanation:

$\frac{sec29^{\circ}}{cosec61^{\circ}}+2cot8^{\circ}cot17^{\circ}cot45^{\circ}cot73^{\circ}cot82^{\circ}-3(sin^{2}38^{\circ}+sin^{2}52^{\circ})$

$\frac{sec29^{\circ}}{sec29^{\circ}}+2cot8^{\circ}cot17^{\circ}(1)cot(90-17)cot(90-8)-3(sin^{2}38^{\circ}+cos^{2}38^{\circ})$

$1+2cot8^{\circ}cot17^{\circ}tan17^{\circ}tan8^{\circ}-3(1)$

$1+2(1)-3$

$3-3$

$0$