evaluate : sec41 .sin49+cos49.cosec41-2/√3 tan20.tan60.tan70-3(cos square 45-- sin square 90)
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Sec 41× sin(90-41) + cos(90-41)× cosec41 - 2 / 3^1/2 × tan (90-70)× 3^1/2 × tan 70 - 3(1/2 -1)
=( sec 41× cos 41 )+( sin 41× cosec 41 )-(2× cot70 × tan70) -3(-1/2)
= 1 + 1 - 2 + 3/2
= 3/2.
Sin(90-x)= cos x
Cos(90-x) = sin x
Tan(90-x)= cot x
Cotx × tanx =1
Sin × cosec=1
Cos × sec=1
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Thank you
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