evaluate : sec41°sin+cos29cosec61°
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Answered by
9
Answer:
yaar question is not clear....
sin??
I think sin 49°
=sec41°sin49°+cos29°cosec61°
=sec(90-49)sin49°+cos29°cosec(90°-29°)
=cosec49°sin49°+cos29°sec29°
=1/sin49° ×sin49°+cos29°×1/cos29°
=1+1
=2
Answered by
1
Answer:
do it from NCERT solutions.
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