Math, asked by mansithestar2005, 9 months ago

evaluate : sec41°sin+cos29cosec61°

Answers

Answered by nagakalakoppalli

9

Answer:

yaar question is not clear....

sin??

I think sin 49°

=sec41°sin49°+cos29°cosec61°

=sec(90-49)sin49°+cos29°cosec(90°-29°)

=cosec49°sin49°+cos29°sec29°

=1/sin49° ×sin49°+cos29°×1/cos29°

=1+1

=2

Answered by vaibhavi855

1

Answer:

do it from NCERT solutions.

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