Evaluate sec70°.sin20°-cos70°.cosec20°
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we know that sec@ = cosec(90-@)
and cosec@ = sec (90-@)
thereore
cosec (90-70) × sin20 -cos70×sec (90-20)
cosec20×sin20-cos70×sec70
1/sin20×sin20-cos70×1/cos70
1-1 =0
and why u categorised this question in english??
thanks plz mark as brainliest
and cosec@ = sec (90-@)
thereore
cosec (90-70) × sin20 -cos70×sec (90-20)
cosec20×sin20-cos70×sec70
1/sin20×sin20-cos70×1/cos70
1-1 =0
and why u categorised this question in english??
thanks plz mark as brainliest
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