Evaluate sigma(2+3^k),where k=1,2,3..11 ?
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Answer
K=1
∑
11
(2+3
K
)
=
K=1
∑
11
2+
K=1
∑
11
3
K
=11×2+
(3−1)
(3)(3
11
−1)
=22+
2
3
(3
11
−1)
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