Math, asked by ritugoel2609, 1 month ago

evaluate:

sin^-1(sin3)​

Answers

Answered by rvss9316
0

Answer:

3

Step-by-step explanation:

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Answered by vijayababu825
0

Answer:

sin–1(sin x) = x Provided x ∈ [ − π 2 , π 2 ] [−π2,π2] ≈ [–1.57,1.57] And in our equation x is 3 which does not lie in the above range. We know sin[π – x] = sin[x] ∴ sin(π – 3) = sin(3) Also π–3 belongs in [ − π 2 , π 2 ] [−π2,π2] ∴ sin–1(sin3) = π–3Read more on Sarthaks.com - https://www.sarthaks.com/1055125/evaluate-each-of-the-following-sin-1-sin-3

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