Question

evaluate: (sin 18) (cos 36)

Answer 1

Answer:

$(sin 18^{\circ})(cos 36^{\circ})=0.25$

Step-by-step explanation:

Given : $(sin 18^{\circ})(cos 36^{\circ})$ ........(1)

Evaluate:

$sin(18^{\circ})= 0.309$

$cos(36^{\circ})= 0.809$

Putting value in equation (1) we get,

$(sin 18^{\circ})(cos 36^{\circ})$

$=(0.309)(0.809)$

$=0.309\times0.809$

$=0.249$

$=0.25$

Therefore, $(sin 18^{\circ})(cos 36^{\circ})=0.25$

Answer 2

Answer:

Step-by-step explanation: