Math, asked by anasmujawar, 1 year ago

Evaluate: Sin 18°\Cos72°​

Answers

Answered by karanjotgaidu
9

\huge\underline\bold\color{red}\mathfrak{Answer}

= sin 18°/cos72°

= sin(90 - 72)°/cos72°

= cos72°/cos72°

= 1

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Answered by madhulachu
1

Answer:

sin18°\cos72°

=sin18°\sin(90°-18°)

sin18°\sin18°

1//

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